Base | Representation |
---|---|
bin | 1001101111000100101110… |
… | …01011101000000010110011 |
3 | 2210210122110212101002201011 |
4 | 10313202113023220002303 |
5 | 10301224410233113413 |
6 | 113310555525251351 |
7 | 4336503250321633 |
oct | 467422713500263 |
9 | 83718425332634 |
10 | 21408653410483 |
11 | 69043a4800739 |
12 | 2499182863b57 |
13 | bc3a9a90a131 |
14 | 540281c1c6c3 |
15 | 271d4ca5e33d |
hex | 1378972e80b3 |
21408653410483 has 4 divisors (see below), whose sum is σ = 21516234583600. Its totient is φ = 21301072237368.
The previous prime is 21408653410457. The next prime is 21408653410511. The reversal of 21408653410483 is 38401435680412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21408653410483 - 217 = 21408653279411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21408653410583) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53790586260 + ... + 53790586657.
It is an arithmetic number, because the mean of its divisors is an integer number (5379058645900).
Almost surely, 221408653410483 is an apocalyptic number.
21408653410483 is a deficient number, since it is larger than the sum of its proper divisors (107581173117).
21408653410483 is a wasteful number, since it uses less digits than its factorization.
21408653410483 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107581173116.
The product of its (nonzero) digits is 2211840, while the sum is 49.
The spelling of 21408653410483 in words is "twenty-one trillion, four hundred eight billion, six hundred fifty-three million, four hundred ten thousand, four hundred eighty-three".
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