Base | Representation |
---|---|
bin | 110000101011110000011000… |
… | …101000111111111011101001 |
3 | 1001002010000101200111220120020 |
4 | 300223300120220333323221 |
5 | 211031012133444303001 |
6 | 2035214113311551053 |
7 | 63046106534656422 |
oct | 6053603050777351 |
9 | 1032100350456506 |
10 | 214113123041001 |
11 | 6224a958047a68 |
12 | 2002068382b489 |
13 | 9261a1c744382 |
14 | 3ac31b7d4a649 |
15 | 19b4891330736 |
hex | c2bc18a3fee9 |
214113123041001 has 4 divisors (see below), whose sum is σ = 285484164054672. Its totient is φ = 142742082027332.
The previous prime is 214113123040951. The next prime is 214113123041023. The reversal of 214113123041001 is 100140321311412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 214113123041001 - 26 = 214113123040937 is a prime.
It is not an unprimeable number, because it can be changed into a prime (214113123041801) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35685520506831 + ... + 35685520506836.
It is an arithmetic number, because the mean of its divisors is an integer number (71371041013668).
Almost surely, 2214113123041001 is an apocalyptic number.
It is an amenable number.
214113123041001 is a deficient number, since it is larger than the sum of its proper divisors (71371041013671).
214113123041001 is an equidigital number, since it uses as much as digits as its factorization.
214113123041001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71371041013670.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 214113123041001 its reverse (100140321311412), we get a palindrome (314253444352413).
The spelling of 214113123041001 in words is "two hundred fourteen trillion, one hundred thirteen billion, one hundred twenty-three million, forty-one thousand, one".
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