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21411432313 = 61313492323
BaseRepresentation
bin10011111100001110…
…001000011101111001
32001021012101110101121
4103330032020131321
5322322311313223
613500345145241
71355411112625
oct237416103571
961235343347
1021411432313
119098217007
12419678b221
132032c29b9b
141071932185
15854b1d15d
hex4fc388779

21411432313 has 4 divisors (see below), whose sum is σ = 21414930768. Its totient is φ = 21407933860.

The previous prime is 21411432281. The next prime is 21411432319. The reversal of 21411432313 is 31323411412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21411432313 - 25 = 21411432281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21411432319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1740031 + ... + 1752292.

It is an arithmetic number, because the mean of its divisors is an integer number (5353732692).

Almost surely, 221411432313 is an apocalyptic number.

It is an amenable number.

21411432313 is a deficient number, since it is larger than the sum of its proper divisors (3498455).

21411432313 is an equidigital number, since it uses as much as digits as its factorization.

21411432313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3498454.

The product of its digits is 1728, while the sum is 25.

Adding to 21411432313 its reverse (31323411412), we get a palindrome (52734843725).

The spelling of 21411432313 in words is "twenty-one billion, four hundred eleven million, four hundred thirty-two thousand, three hundred thirteen".

Divisors: 1 6131 3492323 21411432313