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2141300013303 = 31183781781677
BaseRepresentation
bin11111001010001111011…
…011010011100011110111
321120201001212202020201010
4133022033123103203313
5240040340300411203
64315411042403303
7310463260541433
oct37121733234367
97521055666633
102141300013303
11756136041190
122a6bb9060533
13126c015673b9
14758d4a039c3
153aa77de3303
hex1f28f6d38f7

2141300013303 has 16 divisors (see below), whose sum is σ = 3152143725696. Its totient is φ = 1282121948640.

The previous prime is 2141300013269. The next prime is 2141300013329. The reversal of 2141300013303 is 3033100031412.

It is not a de Polignac number, because 2141300013303 - 226 = 2141232904439 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2141300013303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2141300013383) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 390888100 + ... + 390893577.

It is an arithmetic number, because the mean of its divisors is an integer number (197008982856).

Almost surely, 22141300013303 is an apocalyptic number.

2141300013303 is a deficient number, since it is larger than the sum of its proper divisors (1010843712393).

2141300013303 is a wasteful number, since it uses less digits than its factorization.

2141300013303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 781781774.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 2141300013303 its reverse (3033100031412), we get a palindrome (5174400044715).

The spelling of 2141300013303 in words is "two trillion, one hundred forty-one billion, three hundred million, thirteen thousand, three hundred three".

Divisors: 1 3 11 33 83 249 913 2739 781781677 2345345031 8599598447 25798795341 64887879191 194663637573 713766671101 2141300013303