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21413503 = 79271057
BaseRepresentation
bin101000110101…
…1111001111111
31111021220210201
41101223321333
520440213003
62042544331
7350004016
oct121537177
944256721
1021413503
11110a6311
1272080a7
134589917
142bb5a7d
151d2eb1d
hex146be7f

21413503 has 4 divisors (see below), whose sum is σ = 21684640. Its totient is φ = 21142368.

The previous prime is 21413479. The next prime is 21413531. The reversal of 21413503 is 30531412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21413503 - 25 = 21413471 is a prime.

It is a super-2 number, since 2×214135032 = 917076221462018, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21413533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135450 + ... + 135607.

It is an arithmetic number, because the mean of its divisors is an integer number (5421160).

Almost surely, 221413503 is an apocalyptic number.

21413503 is a deficient number, since it is larger than the sum of its proper divisors (271137).

21413503 is an equidigital number, since it uses as much as digits as its factorization.

21413503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 271136.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 21413503 is about 4627.4726363318. The cubic root of 21413503 is about 277.6914913447.

Adding to 21413503 its reverse (30531412), we get a palindrome (51944915).

The spelling of 21413503 in words is "twenty-one million, four hundred thirteen thousand, five hundred three".

Divisors: 1 79 271057 21413503