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21414342153 = 37138114051
BaseRepresentation
bin10011111100011001…
…001110111000001001
32001021101212021221110
4103330121032320021
5322324032422103
613500531400533
71355444622261
oct237431167011
961241767843
1021414342153
119099924236
124197753149
132033708499
14107208c7a1
15854ee5403
hex4fc64ee09

21414342153 has 4 divisors (see below), whose sum is σ = 28552456208. Its totient is φ = 14276228100.

The previous prime is 21414342137. The next prime is 21414342181. The reversal of 21414342153 is 35124341412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21414342153 - 24 = 21414342137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21414342153.

It is not an unprimeable number, because it can be changed into a prime (21414342193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3569057023 + ... + 3569057028.

It is an arithmetic number, because the mean of its divisors is an integer number (7138114052).

Almost surely, 221414342153 is an apocalyptic number.

It is an amenable number.

21414342153 is a deficient number, since it is larger than the sum of its proper divisors (7138114055).

21414342153 is an equidigital number, since it uses as much as digits as its factorization.

21414342153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7138114054.

The product of its digits is 11520, while the sum is 30.

Adding to 21414342153 its reverse (35124341412), we get a palindrome (56538683565).

The spelling of 21414342153 in words is "twenty-one billion, four hundred fourteen million, three hundred forty-two thousand, one hundred fifty-three".

Divisors: 1 3 7138114051 21414342153