Base | Representation |
---|---|
bin | 110000101101110011100111… |
… | …011111111110110111000111 |
3 | 1001002121111002220112211102012 |
4 | 300231303213133332313013 |
5 | 211040314224310431003 |
6 | 2035402535503004435 |
7 | 63062225441512112 |
oct | 6055634737766707 |
9 | 1032544086484365 |
10 | 214254032514503 |
11 | 622a4696843aa3 |
12 | 20043a49b9971b |
13 | 92720b7868a67 |
14 | 3ac9d4427d579 |
15 | 19b838bd008d8 |
hex | c2dce77fedc7 |
214254032514503 has 16 divisors (see below), whose sum is σ = 227633631852480. Its totient is φ = 201273927515136.
The previous prime is 214254032514493. The next prime is 214254032514547. The reversal of 214254032514503 is 305415230452412.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-214254032514503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214254032514563) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 265049126 + ... + 265856252.
It is an arithmetic number, because the mean of its divisors is an integer number (14227101990780).
Almost surely, 2214254032514503 is an apocalyptic number.
214254032514503 is a deficient number, since it is larger than the sum of its proper divisors (13379599337977).
214254032514503 is a wasteful number, since it uses less digits than its factorization.
214254032514503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1054586.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 214254032514503 its reverse (305415230452412), we get a palindrome (519669262966915).
The spelling of 214254032514503 in words is "two hundred fourteen trillion, two hundred fifty-four billion, thirty-two million, five hundred fourteen thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.126 sec. • engine limits •