Base | Representation |
---|---|
bin | 1001101111100101001011… |
… | …01100101000010110011111 |
3 | 2210212022110010120122021111 |
4 | 10313302211230220112133 |
5 | 10302021101131001303 |
6 | 113323000453242451 |
7 | 4340661104643643 |
oct | 467624554502637 |
9 | 83768403518244 |
10 | 21426076812703 |
11 | 6910825869702 |
12 | 24a0625933427 |
13 | bc56165469a4 |
14 | 541055c34c23 |
15 | 27251c4bdb6d |
hex | 137ca5b2859f |
21426076812703 has 4 divisors (see below), whose sum is σ = 21426747184648. Its totient is φ = 21425406440760.
The previous prime is 21426076812677. The next prime is 21426076812769. The reversal of 21426076812703 is 30721867062412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21426076812703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21426076852703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335138028 + ... + 335201953.
It is an arithmetic number, because the mean of its divisors is an integer number (5356686796162).
Almost surely, 221426076812703 is an apocalyptic number.
21426076812703 is a deficient number, since it is larger than the sum of its proper divisors (670371945).
21426076812703 is an equidigital number, since it uses as much as digits as its factorization.
21426076812703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670371944.
The product of its (nonzero) digits is 1354752, while the sum is 49.
The spelling of 21426076812703 in words is "twenty-one trillion, four hundred twenty-six billion, seventy-six million, eight hundred twelve thousand, seven hundred three".
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