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214312333441 = 1311635972011
BaseRepresentation
bin1100011110011000000…
…0101011000010000001
3202111011210110120000011
43013212000223002001
512002402424132231
6242242001024521
721324600530443
oct3074600530201
9674153416004
10214312333441
11829867a8148
1235650925141
131729555682b
14a530c5c493
155894c009b1
hex31e602b081

214312333441 has 4 divisors (see below), whose sum is σ = 215948305584. Its totient is φ = 212676361300.

The previous prime is 214312333363. The next prime is 214312333457. The reversal of 214312333441 is 144333213412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214312333441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214312333141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 817985875 + ... + 817986136.

It is an arithmetic number, because the mean of its divisors is an integer number (53987076396).

Almost surely, 2214312333441 is an apocalyptic number.

It is an amenable number.

214312333441 is a deficient number, since it is larger than the sum of its proper divisors (1635972143).

214312333441 is a wasteful number, since it uses less digits than its factorization.

214312333441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1635972142.

The product of its digits is 20736, while the sum is 31.

Adding to 214312333441 its reverse (144333213412), we get a palindrome (358645546853).

The spelling of 214312333441 in words is "two hundred fourteen billion, three hundred twelve million, three hundred thirty-three thousand, four hundred forty-one".

Divisors: 1 131 1635972011 214312333441