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2143134305135 = 52267189072281
BaseRepresentation
bin11111001011111100110…
…000100100101101101111
321120212210201021221001122
4133023330300210231233
5240103114340231020
64320313045531155
7310556603011145
oct37137460445557
97525721257048
102143134305135
1175699749784a
122a742b413abb
131271345a2a95
1475a2a485595
153ab33e72125
hex1f2fcc24b6f

2143134305135 has 8 divisors (see below), whose sum is σ = 2572895613456. Its totient is φ = 1713751145920.

The previous prime is 2143134305099. The next prime is 2143134305167. The reversal of 2143134305135 is 5315034313412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2143134305135 - 210 = 2143134304111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2143134305095 and 2143134305104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94524806 + ... + 94547475.

It is an arithmetic number, because the mean of its divisors is an integer number (321611951682).

Almost surely, 22143134305135 is an apocalyptic number.

2143134305135 is a deficient number, since it is larger than the sum of its proper divisors (429761308321).

2143134305135 is a wasteful number, since it uses less digits than its factorization.

2143134305135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 189074553.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 2143134305135 its reverse (5315034313412), we get a palindrome (7458168618547).

The spelling of 2143134305135 in words is "two trillion, one hundred forty-three billion, one hundred thirty-four million, three hundred five thousand, one hundred thirty-five".

Divisors: 1 5 2267 11335 189072281 945361405 428626861027 2143134305135