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21431441113 = 146291464997
BaseRepresentation
bin10011111101011010…
…011101011011011001
32001022121001000022021
4103331122131123121
5322342422103423
613502342054441
71356043146415
oct237532353331
961277030267
1021431441113
1190a8542a05
1241a141a421
132037114304
14107445dd45
1585677195d
hex4fd69d6d9

21431441113 has 4 divisors (see below), whose sum is σ = 21432920740. Its totient is φ = 21429961488.

The previous prime is 21431441107. The next prime is 21431441137. The reversal of 21431441113 is 31114413412.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4503349449 + 16928091664 = 67107^2 + 130108^2 .

It is a cyclic number.

It is not a de Polignac number, because 21431441113 - 25 = 21431441081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21431444113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717870 + ... + 747127.

It is an arithmetic number, because the mean of its divisors is an integer number (5358230185).

Almost surely, 221431441113 is an apocalyptic number.

It is an amenable number.

21431441113 is a deficient number, since it is larger than the sum of its proper divisors (1479627).

21431441113 is a wasteful number, since it uses less digits than its factorization.

21431441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1479626.

The product of its digits is 1152, while the sum is 25.

Adding to 21431441113 its reverse (31114413412), we get a palindrome (52545854525).

The spelling of 21431441113 in words is "twenty-one billion, four hundred thirty-one million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 14629 1464997 21431441113