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21432012143 = 26317814379
BaseRepresentation
bin10011111101011100…
…101000110101101111
32001022122010000121112
4103331130220311233
5322343043342033
613502402222235
71356051045263
oct237534506557
961278100545
1021432012143
1190a88a2a33
1241a165497b
1320372841b9
14107456c0a3
15856835c48
hex4fd728d6f

21432012143 has 4 divisors (see below), whose sum is σ = 21432852840. Its totient is φ = 21431171448.

The previous prime is 21432012097. The next prime is 21432012157. The reversal of 21432012143 is 34121023412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21432012143 - 210 = 21432011119 is a prime.

It is a super-2 number, since 2×214320121432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21432032143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380873 + ... + 433506.

It is an arithmetic number, because the mean of its divisors is an integer number (5358213210).

Almost surely, 221432012143 is an apocalyptic number.

21432012143 is a deficient number, since it is larger than the sum of its proper divisors (840697).

21432012143 is an equidigital number, since it uses as much as digits as its factorization.

21432012143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 840696.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 21432012143 its reverse (34121023412), we get a palindrome (55553035555).

The spelling of 21432012143 in words is "twenty-one billion, four hundred thirty-two million, twelve thousand, one hundred forty-three".

Divisors: 1 26317 814379 21432012143