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2143340155 = 511231114281
BaseRepresentation
bin111111111000000…
…1100011001111011
312112101001221221201
41333300030121323
513342143341110
6552403115031
7104054043055
oct17760143173
95471057851
102143340155
119aa950200
124b9972a77
13282083b18
1416492c8d5
15c8278b3a
hex7fc0c67b

2143340155 has 24 divisors (see below), whose sum is σ = 2918305152. Its totient is φ = 1508496000.

The previous prime is 2143340137. The next prime is 2143340189. The reversal of 2143340155 is 5510433412.

It is not a de Polignac number, because 2143340155 - 29 = 2143339643 is a prime.

It is a hoax number, since the sum of its digits (28) coincides with the sum of the digits of its distinct prime factors.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 38386 + ... + 75895.

It is an arithmetic number, because the mean of its divisors is an integer number (121596048).

Almost surely, 22143340155 is an apocalyptic number.

2143340155 is a deficient number, since it is larger than the sum of its proper divisors (774964997).

2143340155 is a wasteful number, since it uses less digits than its factorization.

2143340155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114339 (or 114328 counting only the distinct ones).

The product of its (nonzero) digits is 7200, while the sum is 28.

The square root of 2143340155 is about 46296.2218220882. The cubic root of 2143340155 is about 1289.3288488441.

Adding to 2143340155 its reverse (5510433412), we get a palindrome (7653773567).

The spelling of 2143340155 in words is "two billion, one hundred forty-three million, three hundred forty thousand, one hundred fifty-five".

Divisors: 1 5 11 31 55 121 155 341 605 1705 3751 18755 114281 571405 1257091 3542711 6285455 13828001 17713555 38969821 69140005 194849105 428668031 2143340155