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2143350057 = 3714450019
BaseRepresentation
bin111111111000000…
…1110110100101001
312112101002110112110
41333300032310221
513342144200212
6552403232533
7104054113662
oct17760166451
95471073473
102143350057
119aa957692
124b9978749
13282088494
14164932369
15c827ba3c
hex7fc0ed29

2143350057 has 4 divisors (see below), whose sum is σ = 2857800080. Its totient is φ = 1428900036.

The previous prime is 2143350049. The next prime is 2143350061. The reversal of 2143350057 is 7500533412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2143350057 - 23 = 2143350049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2143350017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357225007 + ... + 357225012.

It is an arithmetic number, because the mean of its divisors is an integer number (714450020).

Almost surely, 22143350057 is an apocalyptic number.

It is an amenable number.

2143350057 is a deficient number, since it is larger than the sum of its proper divisors (714450023).

2143350057 is an equidigital number, since it uses as much as digits as its factorization.

2143350057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 714450022.

The product of its (nonzero) digits is 12600, while the sum is 30.

The square root of 2143350057 is about 46296.3287637368. The cubic root of 2143350057 is about 1289.3308343611.

Adding to 2143350057 its reverse (7500533412), we get a palindrome (9643883469).

The spelling of 2143350057 in words is "two billion, one hundred forty-three million, three hundred fifty thousand, fifty-seven".

Divisors: 1 3 714450019 2143350057