Base | Representation |
---|---|
bin | 110000101111000100101111… |
… | …101010011010001111010011 |
3 | 1001002220210221202110022101212 |
4 | 300233010233222122033103 |
5 | 211043231124443203210 |
6 | 2035510543405250335 |
7 | 63101431216566413 |
oct | 6057045752321723 |
9 | 1032823852408355 |
10 | 214341142553555 |
11 | 62328628122706 |
12 | 200588bab639ab |
13 | 927a38aa23874 |
14 | 3ad024941a643 |
15 | 19ba7895c2805 |
hex | c2f12fa9a3d3 |
214341142553555 has 16 divisors (see below), whose sum is σ = 262682480822400. Its totient is φ = 167824190036352.
The previous prime is 214341142553539. The next prime is 214341142553591. The reversal of 214341142553555 is 555355241143412.
It is a cyclic number.
It is not a de Polignac number, because 214341142553555 - 24 = 214341142553539 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171075521 + ... + 172323869.
It is an arithmetic number, because the mean of its divisors is an integer number (16417655051400).
Almost surely, 2214341142553555 is an apocalyptic number.
214341142553555 is a deficient number, since it is larger than the sum of its proper divisors (48341338268845).
214341142553555 is a wasteful number, since it uses less digits than its factorization.
214341142553555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1979038.
The product of its digits is 7200000, while the sum is 50.
Adding to 214341142553555 its reverse (555355241143412), we get a palindrome (769696383696967).
The spelling of 214341142553555 in words is "two hundred fourteen trillion, three hundred forty-one billion, one hundred forty-two million, five hundred fifty-three thousand, five hundred fifty-five".
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