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2144135550113 = 13903154221071
BaseRepresentation
bin11111001100111000011…
…100000001010010100001
321120222101111022102221222
4133030320130001102201
5240112142200100423
64321000254024425
7310623451315544
oct37147034012241
97528344272858
102144135550113
11757360690a37
122a766a7a8115
13127263b5782b
1475ac343885b
153ab91cec3c8
hex1f3387014a1

2144135550113 has 4 divisors (see below), whose sum is σ = 2144289785088. Its totient is φ = 2143981315140.

The previous prime is 2144135550083. The next prime is 2144135550121. The reversal of 2144135550113 is 3110555314412.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2144135550113 - 216 = 2144135484577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2144135550413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77096633 + ... + 77124438.

It is an arithmetic number, because the mean of its divisors is an integer number (536072446272).

Almost surely, 22144135550113 is an apocalyptic number.

It is an amenable number.

2144135550113 is a deficient number, since it is larger than the sum of its proper divisors (154234975).

2144135550113 is a wasteful number, since it uses less digits than its factorization.

2144135550113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154234974.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 2144135550113 in words is "two trillion, one hundred forty-four billion, one hundred thirty-five million, five hundred fifty thousand, one hundred thirteen".

Divisors: 1 13903 154221071 2144135550113