Base | Representation |
---|---|
bin | 1001110000000100110000… |
… | …01101000110010011000100 |
3 | 2210220221012122120122101202 |
4 | 10320002120031012103010 |
5 | 10302310311224442012 |
6 | 113334443033442032 |
7 | 4342131165213662 |
oct | 470023015062304 |
9 | 83827178518352 |
10 | 21443030312132 |
11 | 6917a35657760 |
12 | 24a3977570318 |
13 | bc70b8a08760 |
14 | 541bc368bc32 |
15 | 272bb0a5ccc2 |
hex | 1380983464c4 |
21443030312132 has 48 divisors (see below), whose sum is σ = 44086201229952. Its totient is φ = 8996967386880.
The previous prime is 21443030312107. The next prime is 21443030312141. The reversal of 21443030312132 is 23121303034412.
It is a junction number, because it is equal to n+sod(n) for n = 21443030312095 and 21443030312104.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62661848 + ... + 63003120.
It is an arithmetic number, because the mean of its divisors is an integer number (918462525624).
Almost surely, 221443030312132 is an apocalyptic number.
21443030312132 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
21443030312132 is an abundant number, since it is smaller than the sum of its proper divisors (22643170917820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21443030312132 is a wasteful number, since it uses less digits than its factorization.
21443030312132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 451148 (or 451146 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 21443030312132 its reverse (23121303034412), we get a palindrome (44564333346544).
The spelling of 21443030312132 in words is "twenty-one trillion, four hundred forty-three billion, thirty million, three hundred twelve thousand, one hundred thirty-two".
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