214430314021433 has 4 divisors (see below), whose sum is σ = 218992661128320. Its totient is φ = 209867966914548.

The previous prime is 214430314021351. The next prime is 214430314021457. The reversal of 214430314021433 is 334120413034412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214430314021433 - 2²⁰ = 214430312972857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 214430314021393 and 214430314021402.

It is not an unprimeable number, because it can be changed into a prime (214430314021333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2281173553373 + ... + 2281173553466.

It is an arithmetic number, because the mean of its divisors is an integer number (54748165282080).

Almost surely, 2^{214430314021433} is an apocalyptic number.

It is an amenable number.

214430314021433 is a deficient number, since it is larger than the sum of its proper divisors (4562347106887).

214430314021433 is an equidigital number, since it uses as much as digits as its factorization.

214430314021433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4562347106886.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 214430314021433 its reverse (334120413034412), we get a palindrome (548550727055845).

The spelling of 214430314021433 in words is "two hundred fourteen trillion, four hundred thirty billion, three hundred fourteen million, twenty-one thousand, four hundred thirty-three".