Base | Representation |
---|---|
bin | 11111001101110011110… |
… | …110111011110110001011 |
3 | 21121001221222011210020010 |
4 | 133031303312323312023 |
5 | 240121212402231301 |
6 | 4321243225203003 |
7 | 310660245033600 |
oct | 37156366736613 |
9 | 7531858153203 |
10 | 2145132461451 |
11 | 757822395201 |
12 | 2a78a8630463 |
13 | 127392552bb5 |
14 | 75b799c06a7 |
15 | 3abee5bd5d6 |
hex | 1f373dbbd8b |
2145132461451 has 24 divisors (see below), whose sum is σ = 3327200994960. Its totient is φ = 1225769063232.
The previous prime is 2145132461413. The next prime is 2145132461471. The reversal of 2145132461451 is 1541642315412.
It is not a de Polignac number, because 2145132461451 - 213 = 2145132453259 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2145132461471) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13799065 + ... + 13953653.
It is an arithmetic number, because the mean of its divisors is an integer number (138633374790).
Almost surely, 22145132461451 is an apocalyptic number.
2145132461451 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2145132461451 is a deficient number, since it is larger than the sum of its proper divisors (1182068533509).
2145132461451 is a wasteful number, since it uses less digits than its factorization.
2145132461451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 249003 (or 248996 counting only the distinct ones).
The product of its digits is 115200, while the sum is 39.
Adding to 2145132461451 its reverse (1541642315412), we get a palindrome (3686774776863).
The spelling of 2145132461451 in words is "two trillion, one hundred forty-five billion, one hundred thirty-two million, four hundred sixty-one thousand, four hundred fifty-one".
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