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2145202413151 = 72313324238591
BaseRepresentation
bin11111001101111000000…
…001110001111001011111
321121002010211210200220211
4133031320001301321133
5240121333304210101
64321254204353251
7310662054436450
oct37157001617137
97532124720824
102145202413151
11757858922a26
122a7907b45827
131273a3ba5735
1475b84dcd127
153ac057d9c51
hex1f378071e5f

2145202413151 has 8 divisors (see below), whose sum is σ = 2558253809664. Its totient is φ = 1758799493880.

The previous prime is 2145202413127. The next prime is 2145202413223. The reversal of 2145202413151 is 1513142025412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2145202413151 - 213 = 2145202404959 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2145202413451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6662119135 + ... + 6662119456.

It is an arithmetic number, because the mean of its divisors is an integer number (319781726208).

Almost surely, 22145202413151 is an apocalyptic number.

2145202413151 is a deficient number, since it is larger than the sum of its proper divisors (413051396513).

2145202413151 is a wasteful number, since it uses less digits than its factorization.

2145202413151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13324238621.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 2145202413151 its reverse (1513142025412), we get a palindrome (3658344438563).

The spelling of 2145202413151 in words is "two trillion, one hundred forty-five billion, two hundred two million, four hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 7 23 161 13324238591 93269670137 306457487593 2145202413151