Base | Representation |
---|---|
bin | 1100100000000111010… |
… | …0011011010101100001 |
3 | 202112101022100212002001 |
4 | 3020001310123111201 |
5 | 12004331343313343 |
6 | 242400144524001 |
7 | 21342264255445 |
oct | 3100164332541 |
9 | 675338325061 |
10 | 214778885473 |
11 | 830a6099639 |
12 | 35761020601 |
13 | 1733b0ca419 |
14 | a576bc8825 |
15 | 58c0b5d44d |
hex | 3201d1b561 |
214778885473 has 4 divisors (see below), whose sum is σ = 226083037360. Its totient is φ = 203474733588.
The previous prime is 214778885471. The next prime is 214778885507. The reversal of 214778885473 is 374588877412.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 214778885473 - 21 = 214778885471 is a prime.
It is a super-2 number, since 2×2147788854732 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (214778885471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5652075915 + ... + 5652075952.
It is an arithmetic number, because the mean of its divisors is an integer number (56520759340).
Almost surely, 2214778885473 is an apocalyptic number.
It is an amenable number.
214778885473 is a deficient number, since it is larger than the sum of its proper divisors (11304151887).
214778885473 is a wasteful number, since it uses less digits than its factorization.
214778885473 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11304151886.
The product of its digits is 84295680, while the sum is 64.
The spelling of 214778885473 in words is "two hundred fourteen billion, seven hundred seventy-eight million, eight hundred eighty-five thousand, four hundred seventy-three".
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