Base | Representation |
---|---|
bin | 1100100000010000011… |
… | …0000101011101100111 |
3 | 202112110222012202220011 |
4 | 3020010012011131213 |
5 | 12004421132201103 |
6 | 242404031151051 |
7 | 21343236646423 |
oct | 3100406053547 |
9 | 675428182804 |
10 | 214817068903 |
11 | 831156a9398 |
12 | 35771975487 |
13 | 17345ca9178 |
14 | a57bcc7b83 |
15 | 58c41a1d6d |
hex | 3204185767 |
214817068903 has 16 divisors (see below), whose sum is σ = 228773825280. Its totient is φ = 201279329856.
The previous prime is 214817068891. The next prime is 214817068913. The reversal of 214817068903 is 309860718412.
It is a cyclic number.
It is not a de Polignac number, because 214817068903 - 237 = 77378115431 is a prime.
It is a super-2 number, since 2×2148170689032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214817068913) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 113550 + ... + 665227.
It is an arithmetic number, because the mean of its divisors is an integer number (14298364080).
Almost surely, 2214817068903 is an apocalyptic number.
214817068903 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
214817068903 is a deficient number, since it is larger than the sum of its proper divisors (13956756377).
214817068903 is a wasteful number, since it uses less digits than its factorization.
214817068903 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779046.
The product of its (nonzero) digits is 580608, while the sum is 49.
The spelling of 214817068903 in words is "two hundred fourteen billion, eight hundred seventeen million, sixty-eight thousand, nine hundred three".
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