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21494320131 = 316067445931
BaseRepresentation
bin10100000001001010…
…010100110000000011
32001110222100121002210
4110001022110300003
5323010021221011
613512505513203
71360435464234
oct240112246003
961428317083
1021494320131
11912aa8a939
1241ba4a2803
13204715b82b
14107c94b08b
1585c0426a6
hex501294c03

21494320131 has 8 divisors (see below), whose sum is σ = 28660941504. Its totient is φ = 14328622760.

The previous prime is 21494320129. The next prime is 21494320163. The reversal of 21494320131 is 13102349412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21494320131 - 21 = 21494320129 is a prime.

It is a super-2 number, since 2×214943201312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21494320181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 174765 + ... + 271166.

It is an arithmetic number, because the mean of its divisors is an integer number (3582617688).

Almost surely, 221494320131 is an apocalyptic number.

21494320131 is a deficient number, since it is larger than the sum of its proper divisors (7166621373).

21494320131 is a wasteful number, since it uses less digits than its factorization.

21494320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 462001.

The product of its (nonzero) digits is 5184, while the sum is 30.

Adding to 21494320131 its reverse (13102349412), we get a palindrome (34596669543).

The spelling of 21494320131 in words is "twenty-one billion, four hundred ninety-four million, three hundred twenty thousand, one hundred thirty-one".

Divisors: 1 3 16067 48201 445931 1337793 7164773377 21494320131