Base | Representation |
---|---|
bin | 11111010010010110110… |
… | …010011010010100011011 |
3 | 21121112120010121110110112 |
4 | 133102112302122110123 |
5 | 240211211420223103 |
6 | 4323411425434535 |
7 | 311222223515525 |
oct | 37222662322433 |
9 | 7545503543415 |
10 | 2150013445403 |
11 | 7598a75a273a |
12 | 2a882b19ba4b |
13 | 12798c840695 |
14 | 760bdd40a15 |
15 | 3add7d65cd8 |
hex | 1f496c9a51b |
2150013445403 has 4 divisors (see below), whose sum is σ = 2150140524168. Its totient is φ = 2149886366640.
The previous prime is 2150013445367. The next prime is 2150013445457. The reversal of 2150013445403 is 3045443100512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2150013445403 - 228 = 2149745009947 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2150013445403.
It is not an unprimeable number, because it can be changed into a prime (2150013448403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63514001 + ... + 63547842.
It is an arithmetic number, because the mean of its divisors is an integer number (537535131042).
Almost surely, 22150013445403 is an apocalyptic number.
2150013445403 is a deficient number, since it is larger than the sum of its proper divisors (127078765).
2150013445403 is a wasteful number, since it uses less digits than its factorization.
2150013445403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127078764.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 2150013445403 its reverse (3045443100512), we get a palindrome (5195456545915).
The spelling of 2150013445403 in words is "two trillion, one hundred fifty billion, thirteen million, four hundred forty-five thousand, four hundred three".
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