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215002421451 = 3223889157939
BaseRepresentation
bin1100100000111100100…
…1001001100011001011
3202112221212222122210100
43020033021021203023
512010311104441301
6242434252020443
721350650300026
oct3101711114313
9675855878710
10215002421451
1183200297514
1235803a61723
131737550542c
14a5987761bd
1558d55b6286
hex320f2498cb

215002421451 has 6 divisors (see below), whose sum is σ = 310559053220. Its totient is φ = 143334947628.

The previous prime is 215002421419. The next prime is 215002421477. The reversal of 215002421451 is 154124200512.

It is a happy number.

It is not a de Polignac number, because 215002421451 - 25 = 215002421419 is a prime.

It is a super-3 number, since 3×2150024214513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (215002421351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11944578961 + ... + 11944578978.

Almost surely, 2215002421451 is an apocalyptic number.

215002421451 is a deficient number, since it is larger than the sum of its proper divisors (95556631769).

215002421451 is a wasteful number, since it uses less digits than its factorization.

215002421451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23889157945 (or 23889157942 counting only the distinct ones).

The product of its (nonzero) digits is 3200, while the sum is 27.

Adding to 215002421451 its reverse (154124200512), we get a palindrome (369126621963).

The spelling of 215002421451 in words is "two hundred fifteen billion, two million, four hundred twenty-one thousand, four hundred fifty-one".

Divisors: 1 3 9 23889157939 71667473817 215002421451