Base | Representation |
---|---|
bin | 1001110001110011011001… |
… | …10110100010011101001011 |
3 | 2211010121112111022110112001 |
4 | 10320321230312202131023 |
5 | 10304243440211120021 |
6 | 113422025305131431 |
7 | 4346333215516342 |
oct | 470715466423513 |
9 | 84117474273461 |
10 | 21502432520011 |
11 | 6940148654743 |
12 | 24b3395189b77 |
13 | bcc894660ca1 |
14 | 544a1a9b0b59 |
15 | 2744daa7c091 |
hex | 138e6cda274b |
21502432520011 has 4 divisors (see below), whose sum is σ = 21502497483000. Its totient is φ = 21502367557024.
The previous prime is 21502432519993. The next prime is 21502432520017. The reversal of 21502432520011 is 11002523420512.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21502432520011 - 211 = 21502432517963 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21502432520017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31982446 + ... + 32647843.
It is an arithmetic number, because the mean of its divisors is an integer number (5375624370750).
Almost surely, 221502432520011 is an apocalyptic number.
21502432520011 is a deficient number, since it is larger than the sum of its proper divisors (64962989).
21502432520011 is an equidigital number, since it uses as much as digits as its factorization.
21502432520011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64962988.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 21502432520011 its reverse (11002523420512), we get a palindrome (32504955940523).
The spelling of 21502432520011 in words is "twenty-one trillion, five hundred two billion, four hundred thirty-two million, five hundred twenty thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •