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2150603142251 = 5222834117697
BaseRepresentation
bin11111010010111001111…
…011111011010001101011
321121121002020020011110112
4133102321323323101223
5240213413401023001
64323550133004535
7311242644043364
oct37227173732153
97547066204415
102150603142251
1175a07a453703
122a897478374b
13127a54a6c725
14761383a4b6b
153ae1e9eacbb
hex1f4b9efb46b

2150603142251 has 4 divisors (see below), whose sum is σ = 2150607782232. Its totient is φ = 2150598502272.

The previous prime is 2150603142229. The next prime is 2150603142271. The reversal of 2150603142251 is 1522413060512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2150603142251 is a prime.

It is a super-4 number, since 4×21506031422514 (a number of 50 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2150603142221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1536566 + ... + 2581131.

It is an arithmetic number, because the mean of its divisors is an integer number (537651945558).

Almost surely, 22150603142251 is an apocalyptic number.

2150603142251 is a deficient number, since it is larger than the sum of its proper divisors (4639981).

2150603142251 is an equidigital number, since it uses as much as digits as its factorization.

2150603142251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4639980.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 2150603142251 in words is "two trillion, one hundred fifty billion, six hundred three million, one hundred forty-two thousand, two hundred fifty-one".

Divisors: 1 522283 4117697 2150603142251