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215112042313 = 730730291759
BaseRepresentation
bin1100100001010110101…
…1010100011101001001
3202120020112020222100021
43020111223110131021
512011022140323223
6242453205340441
721353451122260
oct3102553243511
9676215228307
10215112042313
118325715a273
1235834707721
131739213704c
14a5a914d5d7
1558e001b65d
hex3215ad4749

215112042313 has 4 divisors (see below), whose sum is σ = 245842334080. Its totient is φ = 184381750548.

The previous prime is 215112042307. The next prime is 215112042317. The reversal of 215112042313 is 313240211512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 215112042313 - 25 = 215112042281 is a prime.

It is not an unprimeable number, because it can be changed into a prime (215112042317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15365145873 + ... + 15365145886.

It is an arithmetic number, because the mean of its divisors is an integer number (61460583520).

Almost surely, 2215112042313 is an apocalyptic number.

It is an amenable number.

215112042313 is a deficient number, since it is larger than the sum of its proper divisors (30730291767).

215112042313 is an equidigital number, since it uses as much as digits as its factorization.

215112042313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30730291766.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 215112042313 its reverse (313240211512), we get a palindrome (528352253825).

The spelling of 215112042313 in words is "two hundred fifteen billion, one hundred twelve million, forty-two thousand, three hundred thirteen".

Divisors: 1 7 30730291759 215112042313