Base | Representation |
---|---|
bin | 11111010011011000110… |
… | …011111001001100111111 |
3 | 21121122102022220200111012 |
4 | 133103120303321030333 |
5 | 240220444002132203 |
6 | 4324113355145435 |
7 | 311261533626545 |
oct | 37233063711477 |
9 | 7548368820435 |
10 | 2151121130303 |
11 | 75a315886802 |
12 | 2a8a9a14527b |
13 | 127b08182232 |
14 | 761870bdd95 |
15 | 3ae50218bd8 |
hex | 1f4d8cf933f |
2151121130303 has 4 divisors (see below), whose sum is σ = 2151404515728. Its totient is φ = 2150837744880.
The previous prime is 2151121130251. The next prime is 2151121130311. The reversal of 2151121130303 is 3030311211512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2151121130303 - 216 = 2151121064767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2151121130393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141681326 + ... + 141696507.
It is an arithmetic number, because the mean of its divisors is an integer number (537851128932).
Almost surely, 22151121130303 is an apocalyptic number.
2151121130303 is a deficient number, since it is larger than the sum of its proper divisors (283385425).
2151121130303 is an equidigital number, since it uses as much as digits as its factorization.
2151121130303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 283385424.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 2151121130303 its reverse (3030311211512), we get a palindrome (5181432341815).
The spelling of 2151121130303 in words is "two trillion, one hundred fifty-one billion, one hundred twenty-one million, one hundred thirty thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •