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215113451441 = 730730493063
BaseRepresentation
bin1100100001010111000…
…0101100011110110001
3202120020121220120022012
43020111300230132301
512011023020421231
6242453255452305
721353466111440
oct3102560543661
9676217816265
10215113451441
1183257a31a39
1235835087095
131739250b555
14a5a93d8d57
1558e01e8e2b
hex3215c2c7b1

215113451441 has 4 divisors (see below), whose sum is σ = 245843944512. Its totient is φ = 184382958372.

The previous prime is 215113451407. The next prime is 215113451447. The reversal of 215113451441 is 144154311512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 215113451441 - 230 = 214039709617 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 215113451398 and 215113451407.

It is not an unprimeable number, because it can be changed into a prime (215113451447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15365246525 + ... + 15365246538.

It is an arithmetic number, because the mean of its divisors is an integer number (61460986128).

Almost surely, 2215113451441 is an apocalyptic number.

It is an amenable number.

215113451441 is a deficient number, since it is larger than the sum of its proper divisors (30730493071).

215113451441 is an equidigital number, since it uses as much as digits as its factorization.

215113451441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30730493070.

The product of its digits is 9600, while the sum is 32.

Adding to 215113451441 its reverse (144154311512), we get a palindrome (359267762953).

The spelling of 215113451441 in words is "two hundred fifteen billion, one hundred thirteen million, four hundred fifty-one thousand, four hundred forty-one".

Divisors: 1 7 30730493063 215113451441