Base | Representation |
---|---|
bin | 1100100001010111000… |
… | …0101100011110110001 |
3 | 202120020121220120022012 |
4 | 3020111300230132301 |
5 | 12011023020421231 |
6 | 242453255452305 |
7 | 21353466111440 |
oct | 3102560543661 |
9 | 676217816265 |
10 | 215113451441 |
11 | 83257a31a39 |
12 | 35835087095 |
13 | 1739250b555 |
14 | a5a93d8d57 |
15 | 58e01e8e2b |
hex | 3215c2c7b1 |
215113451441 has 4 divisors (see below), whose sum is σ = 245843944512. Its totient is φ = 184382958372.
The previous prime is 215113451407. The next prime is 215113451447. The reversal of 215113451441 is 144154311512.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 215113451441 - 230 = 214039709617 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 215113451398 and 215113451407.
It is not an unprimeable number, because it can be changed into a prime (215113451447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15365246525 + ... + 15365246538.
It is an arithmetic number, because the mean of its divisors is an integer number (61460986128).
Almost surely, 2215113451441 is an apocalyptic number.
It is an amenable number.
215113451441 is a deficient number, since it is larger than the sum of its proper divisors (30730493071).
215113451441 is an equidigital number, since it uses as much as digits as its factorization.
215113451441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30730493070.
The product of its digits is 9600, while the sum is 32.
Adding to 215113451441 its reverse (144154311512), we get a palindrome (359267762953).
The spelling of 215113451441 in words is "two hundred fifteen billion, one hundred thirteen million, four hundred fifty-one thousand, four hundred forty-one".
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