Base | Representation |
---|---|
bin | 11111010011011010101… |
… | …111000100101110110011 |
3 | 21121122111120200020022122 |
4 | 133103122233010232303 |
5 | 240221030233434420 |
6 | 4324120511224455 |
7 | 311262405246320 |
oct | 37233257045663 |
9 | 7548446606278 |
10 | 2151153421235 |
11 | 75a332031425 |
12 | 2a8aa8b1812b |
13 | 127b11a79bb0 |
14 | 7618b4c7b47 |
15 | 3ae52e96725 |
hex | 1f4dabc4bb3 |
2151153421235 has 32 divisors (see below), whose sum is σ = 3262955402112. Its totient is φ = 1324808939520.
The previous prime is 2151153421181. The next prime is 2151153421243. The reversal of 2151153421235 is 5321243511512.
It is not a de Polignac number, because 2151153421235 - 240 = 1051641793459 is a prime.
It is a super-2 number, since 2×21511534212352 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a junction number, because it is equal to n+sod(n) for n = 2151153421195 and 2151153421204.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 63872486 + ... + 63906155.
It is an arithmetic number, because the mean of its divisors is an integer number (101967356316).
Almost surely, 22151153421235 is an apocalyptic number.
2151153421235 is a deficient number, since it is larger than the sum of its proper divisors (1111801980877).
2151153421235 is a wasteful number, since it uses less digits than its factorization.
2151153421235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127778703.
The product of its digits is 36000, while the sum is 35.
Adding to 2151153421235 its reverse (5321243511512), we get a palindrome (7472396932747).
The spelling of 2151153421235 in words is "two trillion, one hundred fifty-one billion, one hundred fifty-three million, four hundred twenty-one thousand, two hundred thirty-five".
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