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2151156042613 = 10238712101003
BaseRepresentation
bin11111010011011010111…
…001000100101101110101
321121122111202121102011201
4133103122321010231311
5240221031421330423
64324121043332501
7311262436444654
oct37233271045565
97548452542151
102151156042613
1175a333561956
122a8aa9981131
13127b124870c6
147618b9ab19b
153ae533132ad
hex1f4dae44b75

2151156042613 has 4 divisors (see below), whose sum is σ = 2151159167488. Its totient is φ = 2151152917740.

The previous prime is 2151156042589. The next prime is 2151156042661. The reversal of 2151156042613 is 3162406511512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2151156042613 - 233 = 2142566108021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2151156052613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26631 + ... + 2074372.

It is an arithmetic number, because the mean of its divisors is an integer number (537789791872).

Almost surely, 22151156042613 is an apocalyptic number.

It is an amenable number.

2151156042613 is a deficient number, since it is larger than the sum of its proper divisors (3124875).

2151156042613 is a wasteful number, since it uses less digits than its factorization.

2151156042613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3124874.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 2151156042613 in words is "two trillion, one hundred fifty-one billion, one hundred fifty-six million, forty-two thousand, six hundred thirteen".

Divisors: 1 1023871 2101003 2151156042613