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21513053504103 = 372146347302749
BaseRepresentation
bin1001110010000111001011…
…11010011000001001100111
32211011121221200120100200020
410321003211322120021213
510304432213144112403
6113430543233450223
74350160343425500
oct471034572301147
984147850510606
1021513053504103
1169446a894a247
1224b545a110973
13c00897bb3365
145453473bdba7
1527490d200453
hex1390e5e98267

21513053504103 has 12 divisors (see below), whose sum is σ = 33367185027000. Its totient is φ = 12293173430832.

The previous prime is 21513053504101. The next prime is 21513053504123. The reversal of 21513053504103 is 30140535031512.

It is not a de Polignac number, because 21513053504103 - 21 = 21513053504101 is a prime.

It is a super-2 number, since 2×215130535041032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21513053504101) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 73173651228 + ... + 73173651521.

It is an arithmetic number, because the mean of its divisors is an integer number (2780598752250).

Almost surely, 221513053504103 is an apocalyptic number.

21513053504103 is a deficient number, since it is larger than the sum of its proper divisors (11854131522897).

21513053504103 is a wasteful number, since it uses less digits than its factorization.

21513053504103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146347302766 (or 146347302759 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 21513053504103 its reverse (30140535031512), we get a palindrome (51653588535615).

The spelling of 21513053504103 in words is "twenty-one trillion, five hundred thirteen billion, fifty-three million, five hundred four thousand, one hundred three".

Divisors: 1 3 7 21 49 147 146347302749 439041908247 1024431119243 3073293357729 7171017834701 21513053504103