Base | Representation |
---|---|
bin | 1100100001101100010… |
… | …0000011001100110001 |
3 | 202120110211022012022021 |
4 | 3020123010003030301 |
5 | 12011213304130223 |
6 | 242510154311441 |
7 | 21355626212611 |
oct | 3103304031461 |
9 | 676424265267 |
10 | 215202411313 |
11 | 832a317289a |
12 | 3585aa28581 |
13 | 173a7a87c26 |
14 | a5b7154a41 |
15 | 58e7e1c65d |
hex | 321b103331 |
215202411313 has 4 divisors (see below), whose sum is σ = 215325597040. Its totient is φ = 215079225588.
The previous prime is 215202411311. The next prime is 215202411337. The reversal of 215202411313 is 313114202512.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 215202411313 - 21 = 215202411311 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (215202411311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61590243 + ... + 61593736.
It is an arithmetic number, because the mean of its divisors is an integer number (53831399260).
Almost surely, 2215202411313 is an apocalyptic number.
It is an amenable number.
215202411313 is a deficient number, since it is larger than the sum of its proper divisors (123185727).
215202411313 is a wasteful number, since it uses less digits than its factorization.
215202411313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123185726.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 215202411313 its reverse (313114202512), we get a palindrome (528316613825).
The spelling of 215202411313 in words is "two hundred fifteen billion, two hundred two million, four hundred eleven thousand, three hundred thirteen".
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