Search a number
-
+
2152140412511 = 3316501934781
BaseRepresentation
bin11111010100010101100…
…100001001011001011111
321121202001100212120211002
4133110111210021121133
5240230040421200021
64324402450020515
7311326021450025
oct37242544113137
97552040776732
102152140412511
1175a79917a5a1
122a912357773b
13127c3b3b0bbb
147624260a715
153aeae95850b
hex1f51590965f

2152140412511 has 4 divisors (see below), whose sum is σ = 2158642347624. Its totient is φ = 2145638477400.

The previous prime is 2152140412507. The next prime is 2152140412517. The reversal of 2152140412511 is 1152140412512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2152140412511 - 22 = 2152140412507 is a prime.

It is a super-3 number, since 3×21521404125113 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2152140412517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3250967060 + ... + 3250967721.

It is an arithmetic number, because the mean of its divisors is an integer number (539660586906).

Almost surely, 22152140412511 is an apocalyptic number.

2152140412511 is a deficient number, since it is larger than the sum of its proper divisors (6501935113).

2152140412511 is an equidigital number, since it uses as much as digits as its factorization.

2152140412511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6501935112.

The product of its (nonzero) digits is 3200, while the sum is 29.

Subtracting from 2152140412511 its reverse (1152140412512), we obtain a palindrome (999999999999).

The spelling of 2152140412511 in words is "two trillion, one hundred fifty-two billion, one hundred forty million, four hundred twelve thousand, five hundred eleven".

Divisors: 1 331 6501934781 2152140412511