Base | Representation |
---|---|
bin | 1100100001101111011… |
… | …0100011010110110111 |
3 | 202120111202012210200120 |
4 | 3020123312203112313 |
5 | 12011230201301411 |
6 | 242511350143023 |
7 | 21356146562211 |
oct | 3103366432667 |
9 | 676452183616 |
10 | 215215650231 |
11 | 832aa69544a |
12 | 35863351a73 |
13 | 173aa741aca |
14 | a5b8bdd5b1 |
15 | 58e9185106 |
hex | 321bda35b7 |
215215650231 has 4 divisors (see below), whose sum is σ = 286954200312. Its totient is φ = 143477100152.
The previous prime is 215215650173. The next prime is 215215650337. The reversal of 215215650231 is 132056512512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215215650231 - 27 = 215215650103 is a prime.
It is a super-2 number, since 2×2152156502312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 215215650192 and 215215650201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215215650131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35869275036 + ... + 35869275041.
It is an arithmetic number, because the mean of its divisors is an integer number (71738550078).
Almost surely, 2215215650231 is an apocalyptic number.
215215650231 is a deficient number, since it is larger than the sum of its proper divisors (71738550081).
215215650231 is an equidigital number, since it uses as much as digits as its factorization.
215215650231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71738550080.
The product of its (nonzero) digits is 18000, while the sum is 33.
The spelling of 215215650231 in words is "two hundred fifteen billion, two hundred fifteen million, six hundred fifty thousand, two hundred thirty-one".
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