Base | Representation |
---|---|
bin | 11111010100011001110… |
… | …111001011110100101010 |
3 | 21121202020101112121210002 |
4 | 133110121313023310222 |
5 | 240230212400341132 |
6 | 4324413543223002 |
7 | 311330555336525 |
oct | 37243167136452 |
9 | 7552211477702 |
10 | 2152212512042 |
11 | 75a825944a8a |
12 | 2a9143747a62 |
13 | 127c50306248 |
14 | 7624c017bbc |
15 | 3aeb5e4b262 |
hex | 1f519dcbd2a |
2152212512042 has 4 divisors (see below), whose sum is σ = 3228318768066. Its totient is φ = 1076106256020.
The previous prime is 2152212512039. The next prime is 2152212512057. The reversal of 2152212512042 is 2402152122512.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1525469539801 + 626742972241 = 1235099^2 + 791671^2 .
It is a junction number, because it is equal to n+sod(n) for n = 2152212511996 and 2152212512014.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 538053128009 + ... + 538053128012.
Almost surely, 22152212512042 is an apocalyptic number.
2152212512042 is a deficient number, since it is larger than the sum of its proper divisors (1076106256024).
2152212512042 is a wasteful number, since it uses less digits than its factorization.
2152212512042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1076106256023.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 2152212512042 its reverse (2402152122512), we get a palindrome (4554364634554).
The spelling of 2152212512042 in words is "two trillion, one hundred fifty-two billion, two hundred twelve million, five hundred twelve thousand, forty-two".
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