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2152321214143 = 4218751018589
BaseRepresentation
bin11111010100100000010…
…101110110011010111111
321121202111222002021000211
4133110200111312122333
5240230423212323033
64324432425133251
7311333345314342
oct37244025663277
97552458067024
102152321214143
1175a88123a531
122a917402a227
13127c699a5909
147625c632459
153aec076e2cd
hex1f5205766bf

2152321214143 has 4 divisors (see below), whose sum is σ = 2152372274920. Its totient is φ = 2152270153368.

The previous prime is 2152321214093. The next prime is 2152321214213. The reversal of 2152321214143 is 3414121232512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2152321214143 - 29 = 2152321213631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2152321211143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25467108 + ... + 25551481.

It is an arithmetic number, because the mean of its divisors is an integer number (538093068730).

Almost surely, 22152321214143 is an apocalyptic number.

2152321214143 is a deficient number, since it is larger than the sum of its proper divisors (51060777).

2152321214143 is an equidigital number, since it uses as much as digits as its factorization.

2152321214143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51060776.

The product of its digits is 11520, while the sum is 31.

Adding to 2152321214143 its reverse (3414121232512), we get a palindrome (5566442446655).

The spelling of 2152321214143 in words is "two trillion, one hundred fifty-two billion, three hundred twenty-one million, two hundred fourteen thousand, one hundred forty-three".

Divisors: 1 42187 51018589 2152321214143