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2152341115 = 5430468223
BaseRepresentation
bin1000000001001010…
…0001111001111011
312120000000020221121
42000102201321323
513401444403430
6553324050111
7104223411661
oct20022417173
95500006847
102152341115
11a04a38811
12500993937
13283bb5a32
14165bd2c31
15c8e55a7a
hex804a1e7b

2152341115 has 4 divisors (see below), whose sum is σ = 2582809344. Its totient is φ = 1721872888.

The previous prime is 2152341101. The next prime is 2152341131. The reversal of 2152341115 is 5111432512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2152341115 - 219 = 2151816827 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2152341115.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215234107 + ... + 215234116.

It is an arithmetic number, because the mean of its divisors is an integer number (645702336).

Almost surely, 22152341115 is an apocalyptic number.

2152341115 is a deficient number, since it is larger than the sum of its proper divisors (430468229).

2152341115 is an equidigital number, since it uses as much as digits as its factorization.

2152341115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 430468228.

The product of its digits is 1200, while the sum is 25.

The square root of 2152341115 is about 46393.3305012693. The cubic root of 2152341115 is about 1291.1311743431.

Adding to 2152341115 its reverse (5111432512), we get a palindrome (7263773627).

The spelling of 2152341115 in words is "two billion, one hundred fifty-two million, three hundred forty-one thousand, one hundred fifteen".

Divisors: 1 5 430468223 2152341115