Base | Representation |
---|---|
bin | 11111010100101000010… |
… | …101110111101111111111 |
3 | 21121202212022122111121021 |
4 | 133110220111313233333 |
5 | 240231212042443221 |
6 | 4324454022045011 |
7 | 311336565224464 |
oct | 37245025675777 |
9 | 7552768574537 |
10 | 2152455437311 |
11 | 75a93aa86373 |
12 | 2a91b0b79767 |
13 | 127c8b73c6ca |
14 | 762723b166b |
15 | 3aecc434041 |
hex | 1f528577bff |
2152455437311 has 4 divisors (see below), whose sum is σ = 2152689893224. Its totient is φ = 2152220981400.
The previous prime is 2152455437303. The next prime is 2152455437333. The reversal of 2152455437311 is 1137345542512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2152455437311 - 23 = 2152455437303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2152455437611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117214185 + ... + 117232546.
It is an arithmetic number, because the mean of its divisors is an integer number (538172473306).
Almost surely, 22152455437311 is an apocalyptic number.
2152455437311 is a deficient number, since it is larger than the sum of its proper divisors (234455913).
2152455437311 is an equidigital number, since it uses as much as digits as its factorization.
2152455437311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234455912.
The product of its digits is 504000, while the sum is 43.
The spelling of 2152455437311 in words is "two trillion, one hundred fifty-two billion, four hundred fifty-five million, four hundred thirty-seven thousand, three hundred eleven".
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