Base | Representation |
---|---|
bin | 11111010100101100010… |
… | …101010101010100001111 |
3 | 21121210000222122211012001 |
4 | 133110230111111110033 |
5 | 240231331213431020 |
6 | 4324504413253131 |
7 | 311341340362114 |
oct | 37245425252417 |
9 | 7553028584161 |
10 | 2152522405135 |
11 | 75a974866283 |
12 | 2a920b4941a7 |
13 | 127c9c58903b |
14 | 7627b24490b |
15 | 3aed326150a |
hex | 1f52c55550f |
2152522405135 has 8 divisors (see below), whose sum is σ = 2583285948000. Its totient is φ = 1721845216224.
The previous prime is 2152522405129. The next prime is 2152522405151. The reversal of 2152522405135 is 5315042252512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2152522405135 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2152522405094 and 2152522405103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21533635 + ... + 21633364.
It is an arithmetic number, because the mean of its divisors is an integer number (322910743500).
Almost surely, 22152522405135 is an apocalyptic number.
2152522405135 is a deficient number, since it is larger than the sum of its proper divisors (430763542865).
2152522405135 is an equidigital number, since it uses as much as digits as its factorization.
2152522405135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43176977.
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 2152522405135 its reverse (5315042252512), we get a palindrome (7467564657647).
The spelling of 2152522405135 in words is "two trillion, one hundred fifty-two billion, five hundred twenty-two million, four hundred five thousand, one hundred thirty-five".
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