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2152713801517 = 5168834164799
BaseRepresentation
bin11111010100110111101…
…111011100111100101101
321121210112022210202122221
4133110313233130330231
5240232224213122032
64324535411435341
7311346153254056
oct37246757347455
97553468722587
102152713801517
1175aa62902204
122a92635b5b51
13128000120236
147629882772d
153aee4e6b597
hex1f537bdcf2d

2152713801517 has 4 divisors (see below), whose sum is σ = 2152718483200. Its totient is φ = 2152709119836.

The previous prime is 2152713801503. The next prime is 2152713801551. The reversal of 2152713801517 is 7151083172512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2152713801517 - 211 = 2152713799469 is a prime.

It is a super-2 number, since 2×21527138015172 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2152713831517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1565517 + ... + 2599282.

It is an arithmetic number, because the mean of its divisors is an integer number (538179620800).

Almost surely, 22152713801517 is an apocalyptic number.

It is an amenable number.

2152713801517 is a deficient number, since it is larger than the sum of its proper divisors (4681683).

2152713801517 is an equidigital number, since it uses as much as digits as its factorization.

2152713801517 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4681682.

The product of its (nonzero) digits is 117600, while the sum is 43.

The spelling of 2152713801517 in words is "two trillion, one hundred fifty-two billion, seven hundred thirteen million, eight hundred one thousand, five hundred seventeen".

Divisors: 1 516883 4164799 2152713801517