Base | Representation |
---|---|
bin | 1001110010100110110001… |
… | …10110101110101001001011 |
3 | 2211020020201201022201112211 |
4 | 10321103120312232221023 |
5 | 10310221432131004120 |
6 | 113442430234445551 |
7 | 4351330553061154 |
oct | 471233066565113 |
9 | 84206651281484 |
10 | 21530014313035 |
11 | 6950911880008 |
12 | 24b87b22938b7 |
13 | c0236ba34187 |
14 | 5460b5bba92b |
15 | 2750a223525a |
hex | 1394d8daea4b |
21530014313035 has 4 divisors (see below), whose sum is σ = 25836017175648. Its totient is φ = 17224011450424.
The previous prime is 21530014313023. The next prime is 21530014313069. The reversal of 21530014313035 is 53031341003512.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21530014313035 - 227 = 21529880095307 is a prime.
It is a super-2 number, since 2×215300143130352 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21530014312988 and 21530014313006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2153001431299 + ... + 2153001431308.
It is an arithmetic number, because the mean of its divisors is an integer number (6459004293912).
Almost surely, 221530014313035 is an apocalyptic number.
21530014313035 is a deficient number, since it is larger than the sum of its proper divisors (4306002862613).
21530014313035 is an equidigital number, since it uses as much as digits as its factorization.
21530014313035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4306002862612.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 21530014313035 its reverse (53031341003512), we get a palindrome (74561355316547).
The spelling of 21530014313035 in words is "twenty-one trillion, five hundred thirty billion, fourteen million, three hundred thirteen thousand, thirty-five".
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