Base | Representation |
---|---|
bin | 11111010101001011001… |
… | …011111011111001111111 |
3 | 21121211101001200011111101 |
4 | 133111023023323321333 |
5 | 240233411222113310 |
6 | 4325032024033531 |
7 | 311360224225321 |
oct | 37251313737177 |
9 | 7554331604441 |
10 | 2153040035455 |
11 | 76010aa74631 |
12 | 2a93349028a7 |
13 | 1280528a4a7a |
14 | 762c9ca9611 |
15 | 3b01390d43a |
hex | 1f54b2fbe7f |
2153040035455 has 8 divisors (see below), whose sum is σ = 2583746464032. Its totient is φ = 1722366414048.
The previous prime is 2153040035441. The next prime is 2153040035561. The reversal of 2153040035455 is 5545300403512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2153040035455 - 211 = 2153040033407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8057179 + ... + 8320108.
It is an arithmetic number, because the mean of its divisors is an integer number (322968308004).
Almost surely, 22153040035455 is an apocalyptic number.
2153040035455 is a deficient number, since it is larger than the sum of its proper divisors (430706428577).
2153040035455 is a wasteful number, since it uses less digits than its factorization.
2153040035455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16403585.
The product of its (nonzero) digits is 180000, while the sum is 37.
Adding to 2153040035455 its reverse (5545300403512), we get a palindrome (7698340438967).
The spelling of 2153040035455 in words is "two trillion, one hundred fifty-three billion, forty million, thirty-five thousand, four hundred fifty-five".
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