Base | Representation |
---|---|
bin | 1001110010100111101100… |
… | …11010000010110101010011 |
3 | 2211020022000021020211011200 |
4 | 10321103312122002311103 |
5 | 10310223441042010120 |
6 | 113442551345242243 |
7 | 4351346053221363 |
oct | 471236632026523 |
9 | 84208007224150 |
10 | 21530510110035 |
11 | 69510467266a3 |
12 | 24b8910333383 |
13 | c0241a677194 |
14 | 54612199a9a3 |
15 | 2750d0a1ce90 |
hex | 1394f6682d53 |
21530510110035 has 24 divisors (see below), whose sum is σ = 37320024231360. Its totient is φ = 11482793071872.
The previous prime is 21530510109949. The next prime is 21530510110051. The reversal of 21530510110035 is 53001101503512.
21530510110035 is a `hidden beast` number, since 2 + 1 + 5 + 3 + 0 + 510 + 110 + 0 + 35 = 666.
It is not a de Polignac number, because 21530510110035 - 215 = 21530510077267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21530510109990 and 21530510110008.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 600502 + ... + 6589508.
It is an arithmetic number, because the mean of its divisors is an integer number (1555001009640).
Almost surely, 221530510110035 is an apocalyptic number.
21530510110035 is a deficient number, since it is larger than the sum of its proper divisors (15789514121325).
21530510110035 is a wasteful number, since it uses less digits than its factorization.
21530510110035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6068907 (or 6068904 counting only the distinct ones).
The product of its (nonzero) digits is 2250, while the sum is 27.
Adding to 21530510110035 its reverse (53001101503512), we get a palindrome (74531611613547).
The spelling of 21530510110035 in words is "twenty-one trillion, five hundred thirty billion, five hundred ten million, one hundred ten thousand, thirty-five".
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