Base | Representation |
---|---|
bin | 1001110010101000110110… |
… | …11110100011101001010101 |
3 | 2211020100121121112122102101 |
4 | 10321110123132203221111 |
5 | 10310231224301100010 |
6 | 113443133203442101 |
7 | 4351400344506424 |
oct | 471243336435125 |
9 | 84210547478371 |
10 | 21531132050005 |
11 | 69513357aa376 |
12 | 24b8a64686331 |
13 | c024b94851b6 |
14 | 5461804152bb |
15 | 27511a42173a |
hex | 13951b7a3a55 |
21531132050005 has 4 divisors (see below), whose sum is σ = 25837358460012. Its totient is φ = 17224905640000.
The previous prime is 21531132049997. The next prime is 21531132050011. The reversal of 21531132050005 is 50005023113512.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12328651843524 + 9202480206481 = 3511218^2 + 3033559^2 .
It is not a de Polignac number, because 21531132050005 - 23 = 21531132049997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2153113204996 + ... + 2153113205005.
It is an arithmetic number, because the mean of its divisors is an integer number (6459339615003).
Almost surely, 221531132050005 is an apocalyptic number.
It is an amenable number.
21531132050005 is a deficient number, since it is larger than the sum of its proper divisors (4306226410007).
21531132050005 is an equidigital number, since it uses as much as digits as its factorization.
21531132050005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4306226410006.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 21531132050005 its reverse (50005023113512), we get a palindrome (71536155163517).
The spelling of 21531132050005 in words is "twenty-one trillion, five hundred thirty-one billion, one hundred thirty-two million, fifty thousand, five".
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