Base | Representation |
---|---|
bin | 110000111101001101000010… |
… | …000001111010001001011001 |
3 | 1001020100122012101020111020001 |
4 | 300331031002001322021121 |
5 | 211210133202001443340 |
6 | 2041533004102333001 |
7 | 63231533613062230 |
oct | 6075150201721131 |
9 | 1036318171214201 |
10 | 215312113312345 |
11 | 62672399875a65 |
12 | 20194b1b12a161 |
13 | 931aacaa969aa |
14 | 3b2523a313b17 |
15 | 19d5b6756729a |
hex | c3d34207a259 |
215312113312345 has 16 divisors (see below), whose sum is σ = 296769029126400. Its totient is φ = 146900669408064.
The previous prime is 215312113312291. The next prime is 215312113312411. The reversal of 215312113312345 is 543213311213512.
It is a cyclic number.
It is not a de Polignac number, because 215312113312345 - 27 = 215312113312217 is a prime.
It is a super-2 number, since 2×2153121133123452 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15456713302 + ... + 15456727231.
It is an arithmetic number, because the mean of its divisors is an integer number (18548064320400).
Almost surely, 2215312113312345 is an apocalyptic number.
It is an amenable number.
215312113312345 is a deficient number, since it is larger than the sum of its proper divisors (81456915814055).
215312113312345 is a wasteful number, since it uses less digits than its factorization.
215312113312345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30913440744.
The product of its digits is 64800, while the sum is 37.
Adding to 215312113312345 its reverse (543213311213512), we get a palindrome (758525424525857).
The spelling of 215312113312345 in words is "two hundred fifteen trillion, three hundred twelve billion, one hundred thirteen million, three hundred twelve thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •