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2153274237941 = 15114260094291
BaseRepresentation
bin11111010101011001001…
…001010110001111110101
321121211222101100212220112
4133111121021112033311
5240234401201103231
64325111151512405
7311366100013361
oct37253111261765
97554871325815
102153274237941
11760220198402
122a939b228705
1312808c275b18
147630d0322a1
153b02927192b
hex1f5592563f5

2153274237941 has 4 divisors (see below), whose sum is σ = 2167534332384. Its totient is φ = 2139014143500.

The previous prime is 2153274237883. The next prime is 2153274237977. The reversal of 2153274237941 is 1497324723512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2153274237941 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2153274237941.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2153274237041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7130046995 + ... + 7130047296.

It is an arithmetic number, because the mean of its divisors is an integer number (541883583096).

Almost surely, 22153274237941 is an apocalyptic number.

It is an amenable number.

2153274237941 is a deficient number, since it is larger than the sum of its proper divisors (14260094443).

2153274237941 is a wasteful number, since it uses less digits than its factorization.

2153274237941 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14260094442.

The product of its digits is 2540160, while the sum is 50.

The spelling of 2153274237941 in words is "two trillion, one hundred fifty-three billion, two hundred seventy-four million, two hundred thirty-seven thousand, nine hundred forty-one".

Divisors: 1 151 14260094291 2153274237941