Base | Representation |
---|---|
bin | 11111010101011101011… |
… | …000100011001101010111 |
3 | 21121212011100010211200212 |
4 | 133111131120203031113 |
5 | 240240022401111210 |
6 | 4325122211400035 |
7 | 311400622215011 |
oct | 37253530431527 |
9 | 7555140124625 |
10 | 2153345332055 |
11 | 760257336475 |
12 | 2a93babb301b |
13 | 1280a0c08648 |
14 | 7631865b1b1 |
15 | 3b030616805 |
hex | 1f55d623357 |
2153345332055 has 16 divisors (see below), whose sum is σ = 2786356994400. Its totient is φ = 1592203991040.
The previous prime is 2153345332049. The next prime is 2153345332069. The reversal of 2153345332055 is 5502335433512.
It is not a de Polignac number, because 2153345332055 - 220 = 2153344283479 is a prime.
It is a super-2 number, since 2×21533453320552 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 276420410 + ... + 276428199.
It is an arithmetic number, because the mean of its divisors is an integer number (174147312150).
Almost surely, 22153345332055 is an apocalyptic number.
2153345332055 is a deficient number, since it is larger than the sum of its proper divisors (633011662345).
2153345332055 is a wasteful number, since it uses less digits than its factorization.
2153345332055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 552848674.
The product of its (nonzero) digits is 810000, while the sum is 41.
The spelling of 2153345332055 in words is "two trillion, one hundred fifty-three billion, three hundred forty-five million, three hundred thirty-two thousand, fifty-five".
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