Base | Representation |
---|---|
bin | 11111010101011101110… |
… | …111001010000011010010 |
3 | 21121212011220020110202112 |
4 | 133111131313022003102 |
5 | 240240031424333344 |
6 | 4325123055345322 |
7 | 311401050342626 |
oct | 37253567120322 |
9 | 7555156213675 |
10 | 2153353355474 |
11 | 7602609165a2 |
12 | 2a9401822242 |
13 | 1280a2787629 |
14 | 76319749186 |
15 | 3b03119dc9e |
hex | 1f55ddca0d2 |
2153353355474 has 4 divisors (see below), whose sum is σ = 3230030033214. Its totient is φ = 1076676677736.
The previous prime is 2153353355443. The next prime is 2153353355479. The reversal of 2153353355474 is 4745533533512.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 2073240015625 + 80113339849 = 1439875^2 + 283043^2 .
It is a super-2 number, since 2×21533533554742 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2153353355479) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 538338338867 + ... + 538338338870.
Almost surely, 22153353355474 is an apocalyptic number.
2153353355474 is a deficient number, since it is larger than the sum of its proper divisors (1076676677740).
2153353355474 is a wasteful number, since it uses less digits than its factorization.
2153353355474 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1076676677739.
The product of its digits is 11340000, while the sum is 50.
Adding to 2153353355474 its reverse (4745533533512), we get a palindrome (6898886888986).
The spelling of 2153353355474 in words is "two trillion, one hundred fifty-three billion, three hundred fifty-three million, three hundred fifty-five thousand, four hundred seventy-four".
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